MATH SOLVE

2 months ago

Q:
# HELP ASAP Given the system of linear equations. x=y+3 y=-4x-3Part A: Solve the linear system of equations by graphing Part B: Use substitution to solve the linear system of equations Part C: Use addition to solve the linear system of equations In your final answer, include all of your work, the graph of the equations and the solution.

Accepted Solution

A:

A) I included a graph, look below.

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3

x = -4x + 0

Add 4x to both sides.

5x = 0

Divide both sides by 5.

x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3

y = 0 - 3

y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3

Subtract y from both sides.

x - y = 3

y = -4x - 3

Add 4x to both sides.

4x + y = -3

Add the equations together.

4x + y = -3

x - y = 3

equals

5x = 0

Divide both sides by 5.

x = 0

Input that into one of the original equations.

0 = y + 3

Subtract 3 from both sides.

-3 = y

(0, -3)

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3

x = -4x + 0

Add 4x to both sides.

5x = 0

Divide both sides by 5.

x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3

y = 0 - 3

y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3

Subtract y from both sides.

x - y = 3

y = -4x - 3

Add 4x to both sides.

4x + y = -3

Add the equations together.

4x + y = -3

x - y = 3

equals

5x = 0

Divide both sides by 5.

x = 0

Input that into one of the original equations.

0 = y + 3

Subtract 3 from both sides.

-3 = y

(0, -3)