MATH SOLVE

4 months ago

Q:
# .A water tank fills through two pipes. Water flows inthrough one pipe at a rate of 25,000 gallons per hourand in through the other pipe at a rate of 45,000gallons per hour. Water leaves the system at a rate of60,000 gallons per hour.There are 3 of these tanks, and each tank holds1 million gallons. Each tank is half full. Water isentering and leaving a tank at the maximumamounts. Determine the number of hours, x, it willtake to fill all 3 tanks one at a time.β

Accepted Solution

A:

Answer:It will take 150 hours to fill all 3 tanks at a time.Step-by-step explanation:Water flows in pipe 1 at a rate of 25,000 gallons per hour.Other pipe at a rate of 45,000 gallons per hour.Water leaves the system at a rate of 60,000 gallons per hour.There are 3 of these tanks and each tank holds 1 million gallons.Each tank is half full.So, total capacity of 3 tanks = 3 millions and it is half full.The water need to be filled = 1.5 millions. At the same time 60,000 gallons of water leaving out.25,000 x + 45,000 x - 60,000 x = 1.5 millions70,000x -60,000x = 150000010,000x = 1500000Dividing both sides by 10,000, we getx = 150 hoursTherefore, it will take 150 hours to fill all 3 tanks at a time.